5x+(x-1)(x+2)=x^2+4

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Solution for 5x+(x-1)(x+2)=x^2+4 equation: 



5x+(x-1)(x+2)=x^2+4

We move all terms to the left:

5x+(x-1)(x+2)-(x^2+4)=0

We get rid of parentheses

-x^2+5x+(x-1)(x+2)-4=0

We multiply parentheses ..

-x^2+(+x^2+2x-1x-2)+5x-4=0

We add all the numbers together, and all the variables

-1x^2+(+x^2+2x-1x-2)+5x-4=0

We get rid of parentheses

-1x^2+x^2+2x-1x+5x-2-4=0

We add all the numbers together, and all the variables

6x-6=0

We move all terms containing x to the left, all other terms to the right

6x=6

x=6/6

x=1

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